太極大師劉師傅握蛋破冰 - 武術 Martial Arts
By Delia
at 2011-10-20T22:23
at 2011-10-20T22:23
Table of Contents
我後來大概有看懂你的意思啦
載重F1 (這點當支點分析 如果是靜力平衡是沒有差的)
↓
==> a──────────∥──────────┐
∥ │
∥ │
∥ │
∥ │
∥ │
∥ │
←─c──────────∥──────────┘
截平面合力 △
F3 ↑
支撐力F2
但是Sorry,這樣做自由體圖你左右向的力就先不平衡了
自由體圖是這樣做的嗎?
再說完整一點
你想要我補的應該是 "==>"這一個吧 但是 這一個力矩不利於下面
也就是說當作他沒有 讓我們簡單的低估吧 !!!
再來說上下界的問題 如果按照積分 應該給定一個 ydF(y)的函數對於y從0 to c
這樣做積分這樣的積分式子根據分析學可以改變成 C - F(y)dy (C為一個常數)
也就是說F(y)dy 積分出來的值越大 原本的函數值就越小
顯然的F(y)dy =< (合力值) * y
所以該值為一個下界 而非是上界
所以,您靜力老師哪位?
我的静力學老師嗎 盧X田
你很喜歡問別人老師是誰ㄟ
那我可以問問你的分析老師是誰嗎(簡單的說就是教你物理數學的人)
--
載重F1 (這點當支點分析 如果是靜力平衡是沒有差的)
↓
==> a──────────∥──────────┐
∥ │
∥ │
∥ │
∥ │
∥ │
∥ │
←─c──────────∥──────────┘
截平面合力 △
F3 ↑
支撐力F2
但是Sorry,這樣做自由體圖你左右向的力就先不平衡了
自由體圖是這樣做的嗎?
再說完整一點
你想要我補的應該是 "==>"這一個吧 但是 這一個力矩不利於下面
也就是說當作他沒有 讓我們簡單的低估吧 !!!
再來說上下界的問題 如果按照積分 應該給定一個 ydF(y)的函數對於y從0 to c
這樣做積分這樣的積分式子根據分析學可以改變成 C - F(y)dy (C為一個常數)
也就是說F(y)dy 積分出來的值越大 原本的函數值就越小
顯然的F(y)dy =< (合力值) * y
所以該值為一個下界 而非是上界
所以,您靜力老師哪位?
我的静力學老師嗎 盧X田
你很喜歡問別人老師是誰ㄟ
那我可以問問你的分析老師是誰嗎(簡單的說就是教你物理數學的人)
--
Tags:
武術
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