2014 ATP年終賽 11/14賽程 - 網球 Tennis

Single - Group A

(1) N Djokovic d (6) T Berdych 62 62
(3) S Wawrinka d (8) M Cilic 63 46 63

Doubles - Group A

(1) B Bryan / M Bryan d (3) A Peya / B Soares 76(3) 76(2)
(8) L Kubot / R Lindstedt d (5) J Rojer / H Tecau 64 76(4)


賽程 - A組第三場小組賽 (台灣時間)

20:00開打
[5] Jean-Julien Rojer (NED) vs [8] Lukasz Kubot (POL) H2H 1-0
Horia Tecau (ROU) Robert Lindstedt (SWE)

不早於22:00
[1] Novak Djokovic (SRB) vs [6] Tomas Berdych (CZE) H2H 16-2

不早於次日02:00
[1] Bob Bryan (USA) vs [3] Alexander Peya (AUT) H2H 7-1
Mike Bryan (USA) Bruno Soares (BRA)

不早於次日04:00
[3] Stan Wawrinka (SUI) vs [8] Marin Cilic (CRO) H2H 7-2

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