2014 ATP年終賽 11/12賽程 - 網球 Tennis

Single - Group A

(1) N Djokovic d (3) S Wawrinka 63 60
(6) T Berdych d (8) M Cilic 63 61

Doubles - Group A

(1) B Bryan / M Bryan d (5) J Rojer / H Tecau 67(4) 63 10-6
(8) L Kubot / R Lindstedt d (3) A Peya / B Soares 64 36 10-6


賽程 - A組第二場小組賽 (台灣時間)

20:00開打
[1] Bob Bryan (USA) vs [5] Jean-Julien Rojer (NED) H2H 3-0
Mike Bryan (USA) Horia Tecau (ROU)

不早於22:00
[6] Tomas Berdych (CZE) vs [8] Marin Cilic (CRO) H2H 5-4

不早於次日02:00
[3] Alexander Peya (AUT) vs [8] Lukasz Kubot (POL) H2H 0-0
Bruno Soares (BRA) Robert Lindstedt (SWE)

不早於次日04:00
[1] Novak Djokovic (SRB) vs [3] Stan Wawrinka (SUI) H2H 15-3

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